(4a-4)^2+(4a-4)+5=(a^2)-3*(a+7)

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Solution for (4a-4)^2+(4a-4)+5=(a^2)-3*(a+7) equation: 



(4a-4)^2+(4a-4)+5=(a^2)-3(a+7)

We move all terms to the left:

(4a-4)^2+(4a-4)+5-((a^2)-3(a+7))=0

We get rid of parentheses

(4a-4)^2+4a-(a^2-3(a+7))-4+5=0



We calculate terms in parentheses: -(a^2-3(a+7)), so:

a^2-3(a+7)

We multiply parentheses

a^2-3a-21

Back to the equation:

-(a^2-3a-21)



We add all the numbers together, and all the variables

4a+(4a-4)^2-(a^2-3a-21)+1=0

We get rid of parentheses

-a^2+4a+(4a-4)^2+3a+21+1=0

We add all the numbers together, and all the variables

-1a^2+7a+(4a-4)^2+22=0

We move all terms containing a to the left, all other terms to the right

-1a^2+7a+(4a-4)^2=-22

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